#include<stdio.h> int main() { int a[4][4]={0,1,2,3,4,5,6,7,8,9,4,5,6,7,8,9}; int i,j,k=3,sum=0; //输出4*4方阵 for(i=0;i<4;i++){ for(j=0;j<4;j++){printf("%d ",a[i][j]);} printf("\n"); } printf("\n"); //取左对角线元素并求和 for(i=0;i<4;i++){ for(j=0;j<4;j++){ if(i==j){//printf("%d ",a[i][j]); sum+=a[i][j]; } }//printf("%d ",a[i][k--]); sum+=a[i][k--]; } printf("sum=%d\n",sum); return 0; }
原创文章,作者:曾确令,如若转载,请注明出处:https://www.zengqueling.com/c%e8%af%ad%e8%a8%80%e4%ba%8c%e7%bb%b4%e6%95%b0%e7%bb%84%e5%9f%ba%e7%a1%80%ef%bc%88%e5%af%b9%e8%a7%92%e7%ba%bf%e5%85%83%e7%b4%a0%e6%b1%82%e5%92%8c%ef%bc%89/